3(1[u+3]1)-6u=12

Solution for 3(1[u+3]1)-6u=12 equation:

Simplifying
3(1[u + 3] * 1) + -6u = 12

Reorder the terms:
3(1[3 + u] * 1) + -6u = 12

Reorder the terms for easier multiplication:
3(1 * 1[3 + u]) + -6u = 12

Multiply 1 * 1
3(1[3 + u]) + -6u = 12
3([3 * 1 + u * 1]) + -6u = 12
3([3 + 1u]) + -6u = 12
(3 * 3 + 1u * 3) + -6u = 12
(9 + 3u) + -6u = 12

Combine like terms: 3u + -6u = -3u
9 + -3u = 12

Solving
9 + -3u = 12

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -3u = 12 + -9

Combine like terms: 9 + -9 = 0
0 + -3u = 12 + -9
-3u = 12 + -9

Combine like terms: 12 + -9 = 3
-3u = 3

Divide each side by '-3'.
u = -1

Simplifying
u = -1